28x^2-27x-36=0

Solution for 28x^2-27x-36=0 equation:

28x^2-27x-36=0

a = 28; b = -27; c = -36;
Δ = b2-4ac
Δ = -272-4·28·(-36)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-69}{2*28}=\frac{-42}{56}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+69}{2*28}=\frac{96}{56}
=1+5/7
$